Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. F = mg …(2) , Difficult word of chapter the tale of melon city. Draw areal velocity versus time graph for mars. The tides in the sea formed by the rising and falling of water level in the sea are due to the gravitational force of attraction which the sun and the moon exert on the water surface in the sea. (ii) Weight = \(\frac{G M m}{r^{2}}\), where r is the radius of the earth. Derive an expression for acceleration due to gravity in terms of mass of the earth (M) and universal gravitational constant (G). (b) No. Previous: Contents: Next: (G = 6.67 × 1011 Nm2kg-2) v = 0 + gt2 Question 13. Answer: It also implies that a body orbiting in space has zero weight with respect to a spaceship. F = \(G \frac{m M}{R^{2}}\) …..(1) It is denoted by ‘g’. The Following Section consists of Gravitation Questions on Physics. As we know s = ut + \(\frac{1}{2}\) gt2 For example, given the weight of, and distance between, two objects, you can calculate how large the force of gravity is between them. The universal law of gravitation was able to explain successfully. The astronaut and the spaceship are orbiting with same acceleration hence, the body does not exert any force on the sides of the spaceship. Question 9. Give three differences between acceleration due to gravity (g) and universal gravitational constant (G). It will remain the same on the moon, i.e., 9.8 kg. Suppose gravity of earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? Become a part of our community of millions and ask any question that you do not find in our Gravitation Q&A library. Question 15. When does an object show weightlessness? Answer: Page No: 134. One second later, he throws another stone. As u = 0, h1 = \(\frac{1}{2} g t_{1}^{2}\) Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, The weight will become 16 times. Gravitation Class 9 Extra Questions Short Answer Questions-I. If you are a student of class 9 who is using NCERT Textbook to study Science, then you must come across Chapter 10 Gravitation. h2 = \(\frac{1}{2} g t_{2}^{2}\), How does the force of attraction between the two bodies depend upon their masses and distance between them? Very Short Answer Type Questions. Answer: Answer: According to Newton’s third law of … Question 4. Let the mass, m3 = 0.5 kg be placed at a distance of ‘x’ m from m1, as shown in figure. ∴ For the second stone, v = u + gt2 or, v2 – 02 = 2(-10) × (-40) This force depends on the product of the masses of the planet and sun and the distance between them. Question 1. Thus, equation (3) becomes, State the universal law of gravitation. Question 17. Mention any four phenomena that the universal law of gravitation was able to explain. Question 8. Original weight, W0 = mg = mG \(\frac{M}{R^{2}}\) (2) Answer: This will clear students doubts about any question and improve application skills while preparing for board exams. If the mass of one body is doubled, force is also doubled. Answer: 1. Here are some practice questions that you can try. i.e., the second stone was thrown downward with a speed of 12.1 ms-1. Q.18 What is the weight of a body of mass 1 kg? Then what will happen to your weight? What does a small value of G indicate? Register online for Science tuition on Vedantu.com to score more marks in your examination. (f) Acceleration = 10 ms-2 Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground. Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? ∴ v = u Take g = 9.8 m/s2. Answer: Does the apple also attract the earth? (c) At point B Is weight a force? Weight of the same body on the earth’s surface will be Answer: The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. Answer: Differences between g andG. This hypothesis is not correct. and radius of the moon, Rm = 1740 km If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? Answer: Asked by Umesh 1st December 2017 9:49 AM . Question 19. Answer: (d) What is the ball’s acceleration at point C? Height of the building, h = ? [NCERT Exemplar] Both stones will take the same time to reach the ground because the two stones fall from the same height. But the acceleration due to gravity is represented by the symbol g. Therefore, we can write Derive expression for force of attraction between two bodies and then define gravitational constant. \(\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}\) …. = M + \(\frac{10}{100}\)M = M + \(\frac{M}{10}\) = \(\frac{11M}{10}\) = 1.1 M Give reasons. Question 1. Answer: t1 = \(\frac{u}{g}\) …(1) In order that a body of 5 kg weighs zero at … Both the bodies fall with the same acceleration towards the surface of the earth. ⇒ Average density of the earth, D = \(\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}\) Answer: On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. What is the source of centripetal force that a planet requires to revolve around the sun? Mass of the earth, Me = 6 × 1024 kg Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. Given m1 = 3 kg; m2 = 12 kg Question 2. Similarly, the force of attraction between the earth and the body Q is given by Velocity-time graph for the ball’s motion is shown in figure. What would happen to your weight? Answer: (e) What is the ball’s acceleration at point A? Answer: Why? (a) In which direction is the ball moving at point C? 1. Question 10. Question 7. Two objects of masses ml and m2 having the same size are dropped simultaneously from heights h1 and h2, respectively. Gravitation Class 11 MCQs Questions with Answers. h = 1.27 cm the time taken by the second stone to reach the ground is one second less than that taken by the first stone as both the stones reach the ground at the same time. The ‘G’ is a universal constant, i.e., its value is the same (i.e. Free PDF download of Important Questions with solutions for CBSE Class 9 Science Chapter 10 - Gravitation prepared by expert Science teachers from latest edition of CBSE(NCERT) books. Enter OTP. Comment. Browse from thousands of Gravitation questions and answers (Q&A). Question 1. Weight is not a constant quantity. This test will determine your knowledge of the subject. Question 3. The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. And Radius of the earth, Re = 6.4 × 106 m. Question 7. The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Question 4. Free Question Bank for 11th Class Physics Gravitation Gravitation Conceptual Problems Free Question Bank for NEET Physics Gravitation. 3. The acceleration due to gravity does not depend upon the mass of the stone or body. For the first stone Acceleration, a = g = 9.8 m/s2 Answer: (ii) How long will it take to reach that height? where G is a constant known as universal gravitational constant. Answer: Weight is the force of gravity acting on the body. = 0 – (0.5)2 = 2 × (-9.8) × h We know that F = \(\frac{G M m}{r^{2}}\) as weight of a body is the force with which a body is attracted towards the earth, Answer: Given, Mass of the Sun, M = 2 x 10 30 kg Weight of a body ∝ \(\frac{M}{R^{2}}\) Answer: Give one example each of central force and non-central force. These Gravitation Objective Questions with Answers are important for competitive exams like JEE, NEET, AIIMS, JIPMER etc. If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. Combining (1) and (2), we get Identical packets are dropped from two aeroplanes—one above the equator and other above the north pole, both at height h. Assuming all conditions to be identical, will those packets take same time to reach the surface of earth? [NCERT Exemplar] Yes, fluids have weight. No. Question Answers, Page 134. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. Answer: Question 4. It is different at different places. Professionals, Teachers, Students and Kids Trivia Quizzes to test your knowledge on the subject. State the universal law of gravitation. the mass of body P = m1 Who formulated the universal law of gravitation? Zero. And the mass of body Q=m2 We know that g = \(\frac{G M}{R^{2}}\) or M = \(\frac{g R^{2}}{G}\) Suppose the radius of the earth becomes twice of its present radius without any change in its mass, what will happen to your weight? Answer: OTP has been sent to your mobile number and is valid for one hour Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. We know that G = 6.67 × 10-11 Nm2 kg-2 It’s what keeps us safe on the ground, as opposed to floating up through the air. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. Answer: Question 12. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). part1, Page 1 Define the standard kilogram. Answer: The earth attracts an apple. Find the percentage change in the weight of a body when it is taken from the equator to the poles. Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 8 Gravitation Plus One Physics Gravitation One Mark Questions and Answers Question 1. Zero. Question 3. Question 3. The mass of the Earth M is 5.98 x 1024 kg and the radius of the Earth R is 6.38 x 106 m. (3 marks) Answer. Is the time taken by a body to rise to the highest point equal to the time taken to fall from the same height? Final speed, v = 0 Answer: Using physics, you can calculate the gravitational force that is exerted on one object by another object. ∴ F = ma Show that the weight of an object on the moon is \(\frac{1}{6}\) th of its weight on the earth. This solution contains questions, answers, images, step by step explanations of the complete Chapter 10 titled Gravitation of Science taught in class 9. i.e., weight will increase by 10%. Question 1. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. As per the universal law of gravitation, the force of attraction between the earth and the body P is given by, 1. As the body falls back to the earth with the same velocity it was thrown vertically upwards. In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected? Then force acting on m3 due to m1, is equal and opposite to the force acting on m3 due to m2. F ∝ \(\frac{m_{1} \times m_{2}}{r^{2}}\) The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. When a body is thrown vertically upwards, what is its final velocity? (e) Acceleration = -10 ms-2 Find out the speed with which he threw the second stone. A stone is dropped from a cliff. How does the weight of an object vary with respect to mass and radius of the earth? We know from Newton’s second law of motion that the force is the product of mass and acceleration. g = 9.8 ms-2, h = 49 m, t = 2.16 s, u = ? [NCERT Exemplar] Question 2. When M changes to new mass M’ Question 4. The weight of the body on the moon is about one-sixth of its weight on the earth. u = 0 ms-1, h = 49 m, Q.17 Does the gravitational force same for two objects inside and outside the water? If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. Answer: Answer: [NCERT Exemplar] A stone dropped from the roof of a building takes 4s to reach the ground. Numericals The entire NCERT textbook questions have been solved by best teachers for you. Thus a big stone will fall with the same acceleration as a small stone. A small value of G indicates that the force of gravitational attraction between two ordinary sized objects is a very weak force. On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Find the position of that point. Why does a body orbiting in space possess zero weight with respect to a spaceship? Answer: What will be its speed when it has fallen 100 m? Question 11. 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. […] Question 1. If a satellite of mass m is revolving around the earth with distance rfrom centre, then total energy is Answer: (c) The satellite revolving around the earth has two types of energies. Question 1. radius of the earth, Re = 6400 km If it does, why does the earth not move towards the apple? The gravitational force is responsible for providing the necessary centripetal force which allows the earth to move around the sun at the defined path or orbit. Explain why all of them do not fall into the earth just like an apple falling from a tree. Zero. If the radius of the earth becomes twice of its original radius, then Find out the ratio of time they would take in reaching the ground. Fill in the blanks : _____ of an object is the force of gravity acting on it.. Class 9 - Physics - Gravitation . Calculate the height of the building. A: mass of the object × gravitational acceleration B: Zero For both the stones Answer: NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. Answer: Gravitation is the force of attraction that tends to draw together any two objects in the universe. From the equation (1) and (2), we get The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. Answer: Ratio will not change in either case because acceleration remains the same. Answer: Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. i.e., weight will be reduced to one-fourth of the original. (i) We know v2 – u2 Question 2. % Variation in the weight of a body = % Change in g = 0.7%. Why does formation of tides takes place in sea or ocean? Answer: Assume that g = 10 m/s2 and that there is no air resistance. Answer: (ii) As v = u2 + 2 gs At the equator. A comprehensive database of gravitation quizzes online, test your knowledge with gravitation quiz questions. The radius of the earth at the poles is 6357 km, the radius at the equator is 6378 km. Wm = \(\frac{G M_{m} m}{R_{m}^{2}}\) …(1) Answer: It is different at different places on the surface of the earth. Gravitational force. W = \(\frac{G M m}{(2 r)^{2}}\) We = \(\frac{G M_{e} m}{R_{e}^{2}}\) …(2) Dividing equation (1) by (2), we get So, acceleration = \(\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}\) = 20 m/s2, Question 3. At the poles. At what place on the earth’s surface is the weight of a body minimum? They both hit the ground at the same time. Answer: Answer: What will happen to the gravitational force between two bodies if the masses of one body is doubled? Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. Why? It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. Why can one jump higher on the surface of the moon than on the earth? For the second stone, Calculate the value of acceleration due to gravity g using the relation between g and G. Now, mass of the earth, Me = 6 × 1024 kg Fp = \(\frac{G \times M_{e} \times m_{1}}{R^{2}}\) …..(1) Answer: Question 4. So, v2 = u2 + 2gs, Take the Quiz and improve your overall Physics. Yes. (d) Acceleration = 10 ms-2 [NCERT Exemplar] Answer: Time taken to reach the ground, t = 4 s Answer: ∴ 49 = 0 × t + \(\frac{1}{2}\) × 9.8 × t2 (Where Ve is the volume of the earth) FQ = \(\frac{G \times M_{e} \times m_{2}}{R^{2}}\) ……. F ∝ m1 × m2…(1) Here, initial velocity, u = 0 Do fluids possess weight? Why is ‘G’ called the universal gravitational constant? The time taken for a body is less if the acceleration due to gravity is more when the initial velocities and the distance travelled are the same. Q1. Weight of an object is directly proportional to the mass of the earth and inversely proportional to the square of the radius of the earth, i.e., 1. Downward motion Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. These questions are quite useful to prepare the objective type questions for … or – 0.25 = -19.6 h Answer: When body is at a distance V from centre of the earth then g = \(\frac{G M}{r^{2}}\). Its value also varies from one celestial body to another. But we know, acceleration ∝ 1/m. [NCERT Exemplar] Answer: Class 9 | Science | Chapter 10 |Gravitation| NCERT Solutions. On what factors does that force depend? or, v = \(\sqrt{800}\) Question 1. At what place on the earth’s surface is the weight of a body maximum? Here, if the masses mx and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1 m in the above formula, we get From a cliff of 49 m high, a man drops a stone. 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